= English =
S.M. Vakhterov, student, Moscow State Technical University n.a. N.E. Bauman
M.I. Vakhterov, editor
“The RSA Cryptosystem against Fermat’s Last Theorem”
(Proof The Strong Theorem for The Fermat’s Last Theorem)
About problem to see [P. Ribenboim, 1].
My result:
The Theorem
If
e – prime; e > 2; x, y, z – integers & gcd: (x, y)=(y, z)=(x, z)=1 &
1) (φ(x), φ(y), φ(z), e) = 1, {Euler’s totient φ, to see [2]}{gcd =1}
2) (φ(x), φ(y), φ(z), e) ≠ 1
&
(
≡ 1 (mod x) & (x,e) =1) OR
(
≡ 1 (mod y) & (y,e)
=1) OR
(
≡ 1 (mod z) & (z,e) =1).
It means that Fermat's Last Theorem (FLT) is fair and
+
≠
.
e – prime → φ(e) = e – 1, φ(e) +1 = e.
Euler’s totient φ(q) of a positive integer q is defined to be the number of positive integers less than or equal to n. For example, φ(9) since the six numbers 1, 2, 4, 5, 7 and 8 are coprime to 9.
≡ 1 mod (q), for all a a coprime to q. The totient function also plays a key role in the definition of
the RSA encryption system.
Proof.
( — Begin —
— The Simple Arithmetic restrictions , [1] — )
(1)
+
+
≡ 0 mod x,
+
+
≡ 0 mod y,
+
+
≡ 0 mod z.
If ∃ q : gcd(e, q) = 1 & gcd(x, y, z, q) = 1 ![]()
∃ (b,d): ed = bφ(q)
+1,
+
+
≡
0 mod q, [6].
(2)
+
+
=
+
+ ![]()
(3)
+
+
≡ x + y + z ≡ 0 mod (e)
(4)
>
+
= –
x + y > – z
(4) → (5): x ≢ y mod z; x ≢ –z mod y; y≢ –z mod x.
{x ≡ y (mod z) or x≡ –z (mod y) or y≡ –z (mod x)}
+
≠
.
( — End — The Simple Arithmetic restrictions — )
( — Begin —
— Algorithm The RSA Cryptosystem & Euler’s Theorem,to see [3], [4] —
)
(R1) if (φ(x),e) =
1
encrypt
key (e, mod x) ![]()
z ≢ y → (encrypt) →
≢
(mod x)
+
≠
.
(R2) if (φ(y),e) =
1
encrypt
key (e, mod y) ![]()
z ≢ x → (encrypt) →
≢
(mod y)
+
≠
.
(R3) if (φ(z),e) =
1
encrypt
key (e, mod z) ![]()
x ≢ y →
≢
(mod z)
+
≠
.
(R4) THE RESULT 1: if (φ(x), φ(y), φ(z), e)
= 1
+
≠
.
( — End — Algorithm RSA Cryptosystem & Euler’s Theorem — )
( — Begin —
— Barlow’s result, to see [1] — )
(B1) (for
):
=
,
,
,
(B2) (for
:
Case 2: (y,e) = e))
=
,
,
,
(B3) (for
:
Case 1: (y,e) = 1))
=
,
,
,
(B4) (for
):
=
,
,
.
(B5) (
=1,
(
=1,
(
=1.
(— End — Barlow’s result — )
(— Begin —
The proof for (φ(x), φ(y), φ(z), e)
= e, The Imitation Legandre [1],[5] — )
(— Begin — (φ(
), e) = e — )
(M1) (B4): x + y =
x ≡ –y mod
.
(М2) (B4) ![]()
/
)
=(
![]()
). Then
(М3)
+
/(x + y) =
=
≡
(mod
).
(М4)
≡
(mod
).
{Euler’s Theorem. If (a,
) = 1, then
≡ 1 (mod
).}
(М5)
≡
≡ 1 ≡
mod
+
≠
.
(if the second condition of the theorem fairly!)
(— Еnd — (φ(
), e) = e — )
(— Begin — (φ(
), e) = 1 & (φ(
), e) = e — )
(L1)
) =
.
(— Begin — (y, e) = 1 — )
(L2) (B1, B3, B4 & L1)
=
.
(L3) {(φ(
), e) = e & (φ(
), e) = 1}
(φ(
), e) = e.
(L3) 2z ≡
≡
0 mod
,
(L4)
≡
mod
,
(L5)
≡
mod
,
(L6)
≡
1 mod
,
it is impossible
≢0 mod
,
(L7.1 example) The trivial example for prime Sophie Germain:
e: φ(
) = 2e
(L7.2
example)
≡
≡
1 mod
,
(L7.3
example)
≡
1 mod
,
(L7.4
example) 1 + 1+
≡
1 mod
,
(L7.5
example) 2
≡
-1 mod
,
(L7.6
example)
≡
1 mod (
),
(L7.6
example)
≡
1 mod (
),
it is impossible
(— Begin—
Another proof for this part:
Case 1: (y, e) = 1 & (φ(
), e) = e —)
It may be possible:
If
≡ 0 mod
, (φ(
), e) = e
Then may be Barlow’s relations of the “second order”:
:
= –
,
= –
и
= –
.
And (M1-M5), but for - (φ(
), e) = e to make proof.
(— End another proof for this part —)
(— End — (y, e) = 1 —)
(— Begin — Case 2: (y, e) = e — )
(L8) (B1,
B2, B4 & L1)
=
.
(L9)
≡
-
mod
,
{(L9)
}![]()
(L10)
≡
mod
,
(L11) 1 ≡
mod
,
(L12) (ne -1,e) = 1 →
→
1 ≢
mod
→
→
≢0 mod
.
(— End — Case 2: (y, e) = e — )
(— End — (φ(
), e) = 1 & (φ(
), e) = e — )
(— End — proof for (φ(x), φ(y), φ(z), e) = e —)
Final Result:
if (φ(x), φ(y), φ(z), e) ≠ 1 and (the 2-nd condition of the theorem fairly)
+
≠
, (M5, L12)
if (φ(x),
φ(y), φ(z), e) = 1
+
≠
(R4)
+
≠
.
References
1. P. Ribenboim, Fermat's Last Theorem for Amateurs, Springer-Verlag, New York, NY, 1999. pp. xiv+407, ISBN 0-387-98508-5.
2. Euler's_theorem [Vikipedia - http://en.wikipedia.org]. // http://en.wikipedia.org/wiki/Euler's_theorem (Data 28.03.2010).
3. RSA [Vikipedia - http://en.wikipedia.org]. // http://en.wikipedia.org/wiki/RSA (Data 07.04.2010).
4. The RSA Cryptosystem against Last Fermat’s Theorem [2000.ru - http://fermat.2000.ru/fermats/2000ru_vsm_rsa1a_01_04_2010.htm]. // http:// fermat.2000.ru (Data 28.03.2010).
5. Larry Riddle, Sophie Germain and Fermat's Last Theorem [Agnes Scott College - http://www.agnesscott.edu]. // http://www.agnesscott.edu/Lriddle/WOMEN/germain-FLT/SGandFLT.htm (Data 07.04.2010).
6. S.M.Vakhterov,
Generalisation of a Vendt’s criterion (trivial case) by means of Euler’s theorem
for any integers //
–
2010. – №3(09). – Vol 1. – p. 119. – ISSN 2072-0831.
(E-verison: http://fermat.2000.ru/fermats/vakhterov_vendt_criterion.htm)
S.M. Vakhterov, student, Moscow State Technical University n.a. N.E. Bauman
M.I. Vakhterov, editor
Contact: ![]()
http:// www.2000.ru/fermats/rsa_short_proof_fermat_last_theorem_english_vakhterov15-04-2010.htm
Last Modified: April, 29, 2010