S.M. Vakhterov,  student, Moscow State Technical University n.a. N.E. Bauman

M.I. Vakhterov, editor

 

“The RSA Cryptosystem against Fermat’s Last Theorem”

(Proof The Strong Theorem for The Fermat’s Last Theorem)

 

About problem to see [P. Ribenboim, 1].

My result:

The Theorem

 If

e – prime; e > 2;  x, y, z integers & gcd: (x, y)=(y, z)=(x, z)=1 &

1)    (φ(x), φ(y), φ(z), e) = 1, {Euler’s totient  φ, to see [2]}{gcd =1}

2)    (φ(x), φ(y), φ(z), e) ≠ 1 &
(
≡ 1 (mod x) & (x,e) =1) OR
(≡ 1 (mod y) & (y,e) =1) OR
(
≡ 1 (mod z) & (z,e) =1).

 

It means that Fermat's Last Theorem (FLT) is fair and + .

 

e – prime  →  φ(e) = e – 1, φ(e) +1 = e.

Euler’s totient  φ(q) of a positive integer q is defined to be the number of positive integers less than or equal to n. For example,  φ(9) since the six numbers 1, 2, 4, 5, 7 and 8 are coprime to 9.

 ≡ 1 mod (q), for all a a coprime to q. The totient function also plays a key role in the definition of the RSA encryption system.

 

Proof.

( — Begin
—  The Simple Arithmetic restrictions , [1] — )

(1)                     +  +  ≡ 0 mod x,
 +  +  ≡ 0 mod y,
 +  +  ≡ 0 mod z.

If  q :  gcd(e, q) = 1 & gcd(x, y, z, q) = 1

  ∃ (b,d): ed = bφ(q) +1, +  +  ≡ 0 mod q, [6].

(2)     +  +  =  +  +

(3)     +  +   x + y + z ≡ 0 mod (e)

(4)    >  +  =   x + y > z

(4)   (5): x y mod z;  x z mod yyz mod x.

{x y (mod z) or xz (mod y) or yz (mod x)}  +.

( — End —  The Simple Arithmetic restrictions — )

 ( — Begin
Algorithm The RSA Cryptosystem & Euler’s Theorem,to see [3], [4] — )

 (R1) if (φ(x),e) = 1   encrypt key (e, mod x)

z y(encrypt)   (mod x) +.

(R2) if (φ(y),e) = 1   encrypt key (e, mod y)

z x(encrypt)   (mod y) +.

(R3) if (φ(z),e) = 1   encrypt key (e, mod z)

x y  (mod z) +.

 (R4) THE RESULT 1: if (φ(x), φ(y), φ(z), e) = 1 +.

( — End —  Algorithm RSA Cryptosystem & Euler’s Theorem — )

( — Begin
Barlow’s result,  to see [1] — )

(B1) (for ):

=, , ,

(B2) (for : Case 2: (y,e) = e))

=, , ,

(B3) (for : Case 1: (y,e) = 1))

=, , ,

(B4) (for ):

 = , .

(B5) (=1, (=1, (=1.

(— EndBarlow’s result — )

(— Begin
The proof for (φ(x), φ(y), φ(z), e) = e, The  Imitation Legandre [1],[5] — )

(— Begin(φ(), e) = e — )

(M1) (B4): x + y =    x y mod .

(М2) (B4)

/) =( 

 ). Then

(М3) +/(x + y) =

 =  ≡

   (mod ).

(М4)  ≡  (mod ).

{Euler’s Theorem. If (a, ) = 1, then   1 (mod ).}

(М5)  ≡ ≡ 1  mod +.

(if  the second condition of the theorem fairly!)

(— Еnd (φ(), e) = e — )

(— Begin(φ(), e) = 1 & (φ(), e) = e — )

(L1)  ) = .

(— Begin(y, e) = 1 — )

(L2) (B1, B3, B4 & L1)   = .

(L3) {(φ(), e) = e & (φ(), e) = 1} (φ(), e) = e.

(L3) 2z ≡ 0 mod,

(L4)  ≡  mod ,

(L5)  ≡    mod,

(L6)  ≡ 1 mod, it is impossible

   0 mod,

(L7.1 example) The trivial example for prime Sophie Germain:

e: φ() = 2e

(L7.2 example)   ≡ 1 mod ,

(L7.3 example) ≡  1 mod ,

(L7.4 example) 1 + 1+ ≡  1 mod ,

(L7.5 example) 2≡  -1 mod ,

(L7.6 example) ≡  1 mod (),

(L7.6 example) ≡  1 mod (), it is impossible

(— Begin— 
Another proof for this part:
Case 1: (y,
e) = 1 & (φ(), e) = e —)

It may be possible:

If  ≡ 0 mod , (φ(), e) = e

Then may be  Barlow’s  relations of the “second order”: :
 = ,  =  и  = .

And (M1-M5), but for - (φ(), e) = e to make proof.

        (— End another proof for this part —)

 (— End(y, e) = 1 —)

(— Begin — Case 2: (y, e) = e — )

(L8) (B1, B2, B4 & L1)   = .

(L9) ≡ - mod , {(L9)  }

(L10)  mod ,

(L11) 1 ≡  mod ,

(L12) (ne -1,e) = 1 

→ 1  mod  →

0 mod .

(— End — Case 2: (y, e) = e — )

(— End(φ(), e) = 1 & (φ(), e) = e — )

 (— Endproof for (φ(x), φ(y), φ(z), e) = e —)

Final Result:

if (φ(x), φ(y), φ(z), e) ≠ 1 and (the 2-nd condition of the theorem fairly)

  +, (M5, L12)

if (φ(x), φ(y), φ(z), e) = 1  +(R4)

+.

References

1. P. Ribenboim, Fermat's Last Theorem for Amateurs, Springer-Verlag, New York, NY, 1999. pp. xiv+407, ISBN 0-387-98508-5.

2.  Euler's_theorem [Vikipedia - http://en.wikipedia.org].  //  http://en.wikipedia.org/wiki/Euler's_theorem (Data 28.03.2010).

3. RSA [Vikipedia - http://en.wikipedia.org].  // http://en.wikipedia.org/wiki/RSA (Data 07.04.2010).

4. The RSA Cryptosystem against Last Fermat’s Theorem [2000.ru - http://fermat.2000.ru/fermats/2000ru_vsm_rsa1a_01_04_2010.htm]. // http:// fermat.2000.ru (Data 28.03.2010).

5. Larry Riddle, Sophie Germain and Fermat's Last Theorem [Agnes Scott College - http://www.agnesscott.edu]. // http://www.agnesscott.edu/Lriddle/WOMEN/germain-FLT/SGandFLT.htm (Data 07.04.2010).

6.  S.M.Vakhterov, Generalisation of a Vendt’s criterion (trivial case) by means of  Euler’s theorem for any integers // – 2010. – №3(09). – Vol 1. – p. 119. – ISSN 2072-0831.
(E-verison: http://fermat.2000.ru/fermats/vakhterov_vendt_criterion.htm)

 

S.M. Vakhterov,  student, Moscow State Technical University n.a. N.E. Bauman

M.I. Vakhterov, editor

 

Contact:

 

http:// www.2000.ru/fermats/rsa_short_proof_fermat_last_theorem_english_vakhterov15-04-2010.htm

 

 

Last Modified: April, 29, 2010